Sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

By Vicky Chhetri September 4, 2022 #coding, #computer science, #string, #Sum of an array as runningSum[i] = sum(nums[0]…nums[i]), #vickychhetri

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Return the running sum of nums.

Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

class Solution(object):
    def runningSum(self, nums):
        """
        :type nums: List[int]
        :rtype: List[int]
        """
        output=[]
        for i in range(1,len(nums)+1):
            sum=0
            for j in range(0,i):
                sum=sum+nums[j]
            output.append(sum)
        return output